3.4.86 \(\int \frac {\tanh ^2(c+d x)}{(e+f x) (a+b \sinh (c+d x))} \, dx\) [386]

Optimal. Leaf size=31 \[ \text {Int}\left (\frac {\tanh ^2(c+d x)}{(e+f x) (a+b \sinh (c+d x))},x\right ) \]

[Out]

Unintegrable(tanh(d*x+c)^2/(f*x+e)/(a+b*sinh(d*x+c)),x)

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Rubi [A]
time = 0.05, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \begin {gather*} \int \frac {\tanh ^2(c+d x)}{(e+f x) (a+b \sinh (c+d x))} \, dx \end {gather*}

Verification is not applicable to the result.

[In]

Int[Tanh[c + d*x]^2/((e + f*x)*(a + b*Sinh[c + d*x])),x]

[Out]

Defer[Int][Tanh[c + d*x]^2/((e + f*x)*(a + b*Sinh[c + d*x])), x]

Rubi steps

\begin {align*} \int \frac {\tanh ^2(c+d x)}{(e+f x) (a+b \sinh (c+d x))} \, dx &=\int \frac {\tanh ^2(c+d x)}{(e+f x) (a+b \sinh (c+d x))} \, dx\\ \end {align*}

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Mathematica [F]
time = 180.00, size = 0, normalized size = 0.00 \begin {gather*} \text {\$Aborted} \end {gather*}

Verification is not applicable to the result.

[In]

Integrate[Tanh[c + d*x]^2/((e + f*x)*(a + b*Sinh[c + d*x])),x]

[Out]

$Aborted

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Maple [A]
time = 180.00, size = 0, normalized size = 0.00 \[\int \frac {\tanh ^{2}\left (d x +c \right )}{\left (f x +e \right ) \left (a +b \sinh \left (d x +c \right )\right )}\, dx\]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(tanh(d*x+c)^2/(f*x+e)/(a+b*sinh(d*x+c)),x)

[Out]

int(tanh(d*x+c)^2/(f*x+e)/(a+b*sinh(d*x+c)),x)

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Maxima [A]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(tanh(d*x+c)^2/(f*x+e)/(a+b*sinh(d*x+c)),x, algorithm="maxima")

[Out]

2*a^2*integrate(-e^(d*x + c)/((a^2*b*f + b^3*f)*x + (a^2*b + b^3)*e - ((a^2*b*f*e^(2*c) + b^3*f*e^(2*c))*x + (
a^2*b*e^(2*c) + b^3*e^(2*c))*e)*e^(2*d*x) - 2*((a^3*f*e^c + a*b^2*f*e^c)*x + (a^3*e^c + a*b^2*e^c)*e)*e^(d*x))
, x) - 2*(b*e^(d*x + c) - a)/((a^2*d*f + b^2*d*f)*x + (a^2*d + b^2*d)*e + ((a^2*d*f*e^(2*c) + b^2*d*f*e^(2*c))
*x + (a^2*d*e^(2*c) + b^2*d*e^(2*c))*e)*e^(2*d*x)) - integrate(2*(b*f*e^(d*x + c) - a*f)/((a^2*d*f^2 + b^2*d*f
^2)*x^2 + 2*(a^2*d*f + b^2*d*f)*x*e + (a^2*d + b^2*d)*e^2 + ((a^2*d*f^2*e^(2*c) + b^2*d*f^2*e^(2*c))*x^2 + 2*(
a^2*d*f*e^(2*c) + b^2*d*f*e^(2*c))*x*e + (a^2*d*e^(2*c) + b^2*d*e^(2*c))*e^2)*e^(2*d*x)), x)

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Fricas [A]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(tanh(d*x+c)^2/(f*x+e)/(a+b*sinh(d*x+c)),x, algorithm="fricas")

[Out]

integral(tanh(d*x + c)^2/(a*f*x + a*e + (b*f*x + b*e)*sinh(d*x + c)), x)

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Sympy [A]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\tanh ^{2}{\left (c + d x \right )}}{\left (a + b \sinh {\left (c + d x \right )}\right ) \left (e + f x\right )}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(tanh(d*x+c)**2/(f*x+e)/(a+b*sinh(d*x+c)),x)

[Out]

Integral(tanh(c + d*x)**2/((a + b*sinh(c + d*x))*(e + f*x)), x)

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Giac [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(tanh(d*x+c)^2/(f*x+e)/(a+b*sinh(d*x+c)),x, algorithm="giac")

[Out]

Timed out

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Mupad [A]
time = 0.00, size = -1, normalized size = -0.03 \begin {gather*} \int \frac {{\mathrm {tanh}\left (c+d\,x\right )}^2}{\left (e+f\,x\right )\,\left (a+b\,\mathrm {sinh}\left (c+d\,x\right )\right )} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(tanh(c + d*x)^2/((e + f*x)*(a + b*sinh(c + d*x))),x)

[Out]

int(tanh(c + d*x)^2/((e + f*x)*(a + b*sinh(c + d*x))), x)

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